25 Bottles of Beer in the Bachelor Pad's Crapbox!
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type out lah..
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No camera phone got digital camera or not?Originally posted by mystiv:dont gek me. i no cam phone
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why u gek me againOriginally posted by ndmmxiaomayi:No camera phone got digital camera or not? -
k then. 1 of the more confusing/tougher questionsOriginally posted by the Bear:type out lah..
topic = differentiation
Suppose one molecule of product C is formed from one molecule of reactant A and one molecule of reactant B, and the initial concentrations of A and B have a common value [A] = [B] = a mol/dm^3, then C =
a^2kt
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akt + 1
where k is a constant. Find the rate of reaction at time t -
Ok lor.Originally posted by mystiv:why u gek me again
Take taxi to coolmyth's house.
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uhh.. just differentiate... [a^2kt] [akt + 1]^-1Originally posted by mystiv:k then. 1 of the more confusing/tougher questions
topic = differentiation
Suppose one molecule of product C is formed from one molecule of reactant A and one molecule of reactant B, and the initial concentrations of A and B have a common value [A] = [B] = a mol/dm^3, then C =
a^2kt
----------
akt + 1
where k is a constant. Find the rate of reaction at time t -
why you gek me again, me have $0 nowOriginally posted by ndmmxiaomayi:Ok lor.
Take taxi to coolmyth's house.
jokin -
erm reaction kinetics?? anyway i think is find dc/dt lor. the differentiation you do by sepearting the term into partial fractions then differentiate.Originally posted by mystiv:k then. 1 of the more confusing/tougher questions
topic = differentiation
Suppose one molecule of product C is formed from one molecule of reactant A and one molecule of reactant B, and the initial concentrations of A and B have a common value [A] = [B] = a mol/dm^3, then C =
a^2kt
----------
akt + 1
where k is a constant. Find the rate of reaction at time t -
done thatOriginally posted by the Bear:uhh.. just differentiate... [a^2kt] [akt + 1]^-1
like that only meh? cannot be mah.. -
I like leh. Since now no money, walk home.Originally posted by mystiv:why you gek me again, me have $0 now
jokin 
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differentiated long agoOriginally posted by hisoka:erm reaction kinetics?? anyway i think is find dc/dt lor. the differentiation you do by sepearting the term into partial fractions then differentiate.
i just dunnoe how to continue -
thats the answer mah i suppose cos the rate of reaction of a and b should theoritcally be the same. but then whats the way of calculationg the reaction kinetics? you studying reaction kinetics should know bah....Originally posted by mystiv:done that
like that only meh? cannot be mah.. -
dunno what it's called...
d/dt [vu] = u dv/dt + v du/dt
or something like that? i forgot..
that's it i would think.. that'll be the rate of reaction...Originally posted by mystiv:done that
like that only meh? cannot be mah.. -
I think so.Originally posted by mystiv:done that
like that only meh? cannot be mah.. -
i at home leh. where you want me walk to?Originally posted by ndmmxiaomayi:I like leh. Since now no money, walk home.
ooh. u mean your home? 
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Walk to the rooftop of your house.Originally posted by mystiv:i at home leh. where you want me walk to?
ooh. u mean your home? -
i know how to differentiateOriginally posted by the Bear:dunno what it's called...
d/dt [vu] = u dv/dt + v du/dt
or something like that? i forgot..
that's it i would think.. that'll be the rate of reaction...
what i meant was, no need to find numerical value meh? -
Product rule can be used for fractions meh?Originally posted by the Bear:dunno what it's called...
d/dt [vu] = u dv/dt + v du/dt
or something like that? i forgot..
that's it i would think.. that'll be the rate of reaction...
I thought is the other one?
(v du/dt - u dv/dt)/v^2 -
you jump i jump?Originally posted by ndmmxiaomayi:Walk to the rooftop of your house. -
why not?
v and u can be anything as long as it's a function of the variableOriginally posted by ndmmxiaomayi:Product rule can be used for fractions meh?
I thought is the other one?
(v du/dt - u dv/dt)/v^2 -
product rule can. just slightly longer routeOriginally posted by ndmmxiaomayi:Product rule can be used for fractions meh?
I thought is the other one?
(v du/dt - u dv/dt)/v^2
just to restate, i have no problems with differentiating -
I think need lah.Originally posted by mystiv:i know how to differentiate
what i meant was, no need to find numerical value meh?
I very bad at differentiation applications. Ask bear or hisoka. -
that's all they seem to ask you..
so that's it...Originally posted by mystiv:product rule can. just slightly longer route
just to restate, i have no problems with differentiating -
You jump, I take lift.Originally posted by mystiv:you jump i jump? -
*alfagal has jus signed in*